mirror of
https://github.com/Luzifer/vault-otp-ui.git
synced 2024-11-10 01:00:09 +00:00
251 lines
5.2 KiB
Go
251 lines
5.2 KiB
Go
package strconv
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import "math"
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var float64pow10 = []float64{
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1e0, 1e1, 1e2, 1e3, 1e4, 1e5, 1e6, 1e7, 1e8, 1e9,
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1e10, 1e11, 1e12, 1e13, 1e14, 1e15, 1e16, 1e17, 1e18, 1e19,
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1e20, 1e21, 1e22,
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}
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// Float parses a byte-slice and returns the float it represents.
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// If an invalid character is encountered, it will stop there.
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func ParseFloat(b []byte) (float64, int) {
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i := 0
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neg := false
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if i < len(b) && (b[i] == '+' || b[i] == '-') {
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neg = b[i] == '-'
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i++
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}
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dot := -1
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trunk := -1
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n := uint64(0)
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for ; i < len(b); i++ {
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c := b[i]
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if c >= '0' && c <= '9' {
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if trunk == -1 {
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if n > math.MaxUint64/10 {
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trunk = i
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} else {
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n *= 10
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n += uint64(c - '0')
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}
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}
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} else if dot == -1 && c == '.' {
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dot = i
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} else {
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break
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}
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}
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f := float64(n)
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if neg {
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f = -f
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}
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mantExp := int64(0)
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if dot != -1 {
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if trunk == -1 {
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trunk = i
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}
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mantExp = int64(trunk - dot - 1)
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} else if trunk != -1 {
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mantExp = int64(trunk - i)
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}
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expExp := int64(0)
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if i < len(b) && (b[i] == 'e' || b[i] == 'E') {
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i++
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if e, expLen := ParseInt(b[i:]); expLen > 0 {
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expExp = e
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i += expLen
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}
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}
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exp := expExp - mantExp
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// copied from strconv/atof.go
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if exp == 0 {
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return f, i
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} else if exp > 0 && exp <= 15+22 { // int * 10^k
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// If exponent is big but number of digits is not,
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// can move a few zeros into the integer part.
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if exp > 22 {
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f *= float64pow10[exp-22]
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exp = 22
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}
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if f <= 1e15 && f >= -1e15 {
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return f * float64pow10[exp], i
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}
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} else if exp < 0 && exp >= -22 { // int / 10^k
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return f / float64pow10[-exp], i
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}
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f *= math.Pow10(int(-mantExp))
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return f * math.Pow10(int(expExp)), i
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}
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const log2 = 0.301029995
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const int64maxlen = 18
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func float64exp(f float64) int {
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exp2 := 0
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if f != 0.0 {
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x := math.Float64bits(f)
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exp2 = int(x>>(64-11-1))&0x7FF - 1023 + 1
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}
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exp10 := float64(exp2) * log2
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if exp10 < 0 {
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exp10 -= 1.0
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}
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return int(exp10)
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}
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func AppendFloat(b []byte, f float64, prec int) ([]byte, bool) {
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if math.IsNaN(f) || math.IsInf(f, 0) {
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return b, false
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} else if prec >= int64maxlen {
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return b, false
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}
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neg := false
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if f < 0.0 {
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f = -f
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neg = true
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}
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if prec == -1 {
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prec = int64maxlen - 1
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}
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prec -= float64exp(f) // number of digits in front of the dot
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f *= math.Pow10(prec)
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// calculate mantissa and exponent
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mant := int64(f)
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mantLen := LenInt(mant)
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mantExp := mantLen - prec - 1
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if mant == 0 {
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return append(b, '0'), true
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}
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// expLen is zero for positive exponents, because positive exponents are determined later on in the big conversion loop
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exp := 0
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expLen := 0
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if mantExp > 0 {
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// positive exponent is determined in the loop below
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// but if we initially decreased the exponent to fit in an integer, we can't set the new exponent in the loop alone,
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// since the number of zeros at the end determines the positive exponent in the loop, and we just artificially lost zeros
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if prec < 0 {
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exp = mantExp
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}
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expLen = 1 + LenInt(int64(exp)) // e + digits
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} else if mantExp < -3 {
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exp = mantExp
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expLen = 2 + LenInt(int64(exp)) // e + minus + digits
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} else if mantExp < -1 {
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mantLen += -mantExp - 1 // extra zero between dot and first digit
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}
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// reserve space in b
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i := len(b)
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maxLen := 1 + mantLen + expLen // dot + mantissa digits + exponent
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if neg {
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maxLen++
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}
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if i+maxLen > cap(b) {
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b = append(b, make([]byte, maxLen)...)
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} else {
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b = b[:i+maxLen]
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}
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// write to string representation
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if neg {
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b[i] = '-'
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i++
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}
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// big conversion loop, start at the end and move to the front
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// initially print trailing zeros and remove them later on
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// for example if the first non-zero digit is three positions in front of the dot, it will overwrite the zeros with a positive exponent
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zero := true
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last := i + mantLen // right-most position of digit that is non-zero + dot
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dot := last - prec - exp // position of dot
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j := last
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for mant > 0 {
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if j == dot {
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b[j] = '.'
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j--
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}
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newMant := mant / 10
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digit := mant - 10*newMant
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if zero && digit > 0 {
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// first non-zero digit, if we are still behind the dot we can trim the end to this position
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// otherwise trim to the dot (including the dot)
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if j > dot {
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i = j + 1
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// decrease negative exponent further to get rid of dot
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if exp < 0 {
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newExp := exp - (j - dot)
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// getting rid of the dot shouldn't lower the exponent to more digits (e.g. -9 -> -10)
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if LenInt(int64(newExp)) == LenInt(int64(exp)) {
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exp = newExp
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dot = j
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j--
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i--
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}
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}
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} else {
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i = dot
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}
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last = j
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zero = false
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}
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b[j] = '0' + byte(digit)
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j--
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mant = newMant
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}
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if j > dot {
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// extra zeros behind the dot
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for j > dot {
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b[j] = '0'
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j--
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}
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b[j] = '.'
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} else if last+3 < dot {
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// add positive exponent because we have 3 or more zeros in front of the dot
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i = last + 1
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exp = dot - last - 1
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} else if j == dot {
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// handle 0.1
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b[j] = '.'
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}
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// exponent
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if exp != 0 {
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if exp == 1 {
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b[i] = '0'
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i++
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} else if exp == 2 {
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b[i] = '0'
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b[i+1] = '0'
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i += 2
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} else {
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b[i] = 'e'
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i++
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if exp < 0 {
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b[i] = '-'
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i++
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exp = -exp
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}
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i += LenInt(int64(exp))
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j := i
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for exp > 0 {
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newExp := exp / 10
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digit := exp - 10*newExp
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j--
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b[j] = '0' + byte(digit)
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exp = newExp
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}
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}
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}
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return b[:i], true
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}
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