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Add ability for XKCD style passwords to workflow
Signed-off-by: Knut Ahlers <knut@ahlers.me>
This commit is contained in:
parent
c8c6485064
commit
8ca878e760
1 changed files with 7 additions and 2 deletions
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@ -20,6 +20,7 @@ descriptions = {
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def main(wf):
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def main(wf):
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password_length = 20
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password_length = 20
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use_special = False
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use_special = False
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use_xkcd = False
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if len(wf.args):
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if len(wf.args):
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for arg in wf.args[0].split():
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for arg in wf.args[0].split():
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@ -27,10 +28,12 @@ def main(wf):
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password_length = int(arg)
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password_length = int(arg)
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elif arg == 's':
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elif arg == 's':
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use_special = True
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use_special = True
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elif arg == 'x':
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use_xkcd = True
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if password_length < 5 or password_length > 256:
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if password_length < 4 or password_length > 256:
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wf.add_item(title="Password length out of bounds",
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wf.add_item(title="Password length out of bounds",
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subtitle="Please use a reasonable password length between 5 and 256")
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subtitle="Please use a reasonable password length between 4 and 256")
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wf.send_feedback()
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wf.send_feedback()
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return 1
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return 1
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@ -39,6 +42,8 @@ def main(wf):
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str(password_length)]
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str(password_length)]
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if use_special:
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if use_special:
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command.append("-s")
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command.append("-s")
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if use_xkcd:
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command.append("-x")
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result = json.loads(subprocess.check_output(command).strip())
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result = json.loads(subprocess.check_output(command).strip())
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hashed = []
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hashed = []
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